WebThe density of a solution prepared by dissolving 1 2 0 g of urea (mol. mass = 6 0 u) in 1 0 0 0 g of water is 1. 1 5 g m L − 1. The molarity of the solution is: The molarity of the … WebOct 7, 2024 · Dissolving 120 g of urea (mol. wt. 60) in 1000 g of water gave a solution of density 1.15 g/mL. The molarity of the solution is . ... Dissolving `120g` of urea (mol wt `= 60)` in 1000g of water gave a solution of density 1.15 g/mL. The molarity of the solution is. asked May 11, 2024 in Chemistry by Prishabasu (96.2k points)
CBSE Class 11-science Answered - TopperLearning
WebNov 4, 2024 · the density of a solution prepared by dissolving 120g of urea in 1000g of water is 1.15g/ml .find the molarity & molality of this solution 2 See answers Advertisement Advertisement ... = 120 g / 60.05 g = 2 mol [since, molecular mass of urea is 60.05 g] Now ,M(Molarity) = n (no. of moles of solute)/ Volume of solution in litres ... WebMost recent answer. Urea is soluble in water (107.9 g/100 ml at 20 °C) and when dissolved, it is neutral on the pH scale. Urea is soluble in glycerol (500 g/L) and slightly less soluble in ... blinds for between the glass windows
How would you calculate the vapor pressure of a solution made …
WebMar 20, 2024 · Dissolving 120 g of urea (mol. wt. 60) in 1000 g of water gave a solution of density 1.15 g/mL . The molarity of the solution is: A: 1.78 M B: 2.0 M C: 2.05 M D: 2.22 … WebNov 30, 2024 · Assume we want to dissolve 70.128 grams of salt in 1.5 kg of water. So: moles of NaCl = 70.128 g / (58.44 g/mol) = 1.2 mol. Plug the number of moles and the mass of the solvent into the molality formula. Divide 1.2 mol by 1.5 kg, ... WebMar 20, 2024 · Dissolving 120 g of urea (mol. wt. 60) in 1000 g of water gave a solution of density 1.15 g/mL . The molarity of the solution is: A: 1.78 M B: 2.0 M C: 2.05 M D: 2.22 M. ... Now, we already know that the solution comprises 120 g of urea (solute) and 1000 g of water (solvent). So, the total mass of the solution becomes: ... frederic weinberg attorney